Base | Representation |
---|---|
bin | 1001111010100100… |
… | …11100111010100001 |
3 | 111201222120022111111 |
4 | 10331102130322201 |
5 | 41400220330442 |
6 | 2240114543321 |
7 | 245625401536 |
oct | 47522347241 |
9 | 14658508444 |
10 | 5323214497 |
11 | 22918a7927 |
12 | 1046897b41 |
13 | 66aac6c83 |
14 | 386d98d8d |
15 | 2124edb17 |
hex | 13d49cea1 |
5323214497 has 2 divisors, whose sum is σ = 5323214498. Its totient is φ = 5323214496.
The previous prime is 5323214447. The next prime is 5323214513. The reversal of 5323214497 is 7944123235.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5306248336 + 16966161 = 72844^2 + 4119^2 .
It is a cyclic number.
It is not a de Polignac number, because 5323214497 - 211 = 5323212449 is a prime.
It is a super-2 number, since 2×53232144972 = 56673225162141926018, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5323214447) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2661607248 + 2661607249.
It is an arithmetic number, because the mean of its divisors is an integer number (2661607249).
Almost surely, 25323214497 is an apocalyptic number.
It is an amenable number.
5323214497 is a deficient number, since it is larger than the sum of its proper divisors (1).
5323214497 is an equidigital number, since it uses as much as digits as its factorization.
5323214497 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 181440, while the sum is 40.
The square root of 5323214497 is about 72960.3625059525. The cubic root of 5323214497 is about 1746.0552777148.
The spelling of 5323214497 in words is "five billion, three hundred twenty-three million, two hundred fourteen thousand, four hundred ninety-seven".
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