Base | Representation |
---|---|
bin | 100110101110110100101… |
… | …0100010100110100001001 |
3 | 200211220012011001100012212 |
4 | 1031131221110110310021 |
5 | 1144203434220244221 |
6 | 15153243031314505 |
7 | 1056406431314153 |
oct | 115355124246411 |
9 | 20756164040185 |
10 | 5323231415561 |
11 | 177262a3a3154 |
12 | 71b81751ba35 |
13 | 2c7c94bb86c7 |
14 | 145908015ad3 |
15 | 937096a2b5b |
hex | 4d769514d09 |
5323231415561 has 2 divisors, whose sum is σ = 5323231415562. Its totient is φ = 5323231415560.
The previous prime is 5323231415549. The next prime is 5323231415569. The reversal of 5323231415561 is 1655141323235.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3893245943161 + 1429985472400 = 1973131^2 + 1195820^2 .
It is a cyclic number.
It is not a de Polignac number, because 5323231415561 - 210 = 5323231414537 is a prime.
It is not a weakly prime, because it can be changed into another prime (5323231415569) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2661615707780 + 2661615707781.
It is an arithmetic number, because the mean of its divisors is an integer number (2661615707781).
Almost surely, 25323231415561 is an apocalyptic number.
It is an amenable number.
5323231415561 is a deficient number, since it is larger than the sum of its proper divisors (1).
5323231415561 is an equidigital number, since it uses as much as digits as its factorization.
5323231415561 is an evil number, because the sum of its binary digits is even.
The product of its digits is 324000, while the sum is 41.
Adding to 5323231415561 its reverse (1655141323235), we get a palindrome (6978372738796).
The spelling of 5323231415561 in words is "five trillion, three hundred twenty-three billion, two hundred thirty-one million, four hundred fifteen thousand, five hundred sixty-one".
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