Base | Representation |
---|---|
bin | 1111011111101011100… |
… | …00111001110100000001 |
3 | 1212220020011110101122011 |
4 | 13233311300321310001 |
5 | 32210330434340131 |
6 | 1044325542012521 |
7 | 53315321105446 |
oct | 7576560716401 |
9 | 1786204411564 |
10 | 532404215041 |
11 | 195878332906 |
12 | 87225117141 |
13 | 3b28964620a |
14 | 1baa8aa79cd |
15 | dcb08670b1 |
hex | 7bf5c39d01 |
532404215041 has 2 divisors, whose sum is σ = 532404215042. Its totient is φ = 532404215040.
The previous prime is 532404214967. The next prime is 532404215047. The reversal of 532404215041 is 140512404235.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 370716588225 + 161687626816 = 608865^2 + 402104^2 .
It is a cyclic number.
It is not a de Polignac number, because 532404215041 - 27 = 532404214913 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 532404214994 and 532404215012.
It is not a weakly prime, because it can be changed into another prime (532404215047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 266202107520 + 266202107521.
It is an arithmetic number, because the mean of its divisors is an integer number (266202107521).
Almost surely, 2532404215041 is an apocalyptic number.
It is an amenable number.
532404215041 is a deficient number, since it is larger than the sum of its proper divisors (1).
532404215041 is an equidigital number, since it uses as much as digits as its factorization.
532404215041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 532404215041 its reverse (140512404235), we get a palindrome (672916619276).
The spelling of 532404215041 in words is "five hundred thirty-two billion, four hundred four million, two hundred fifteen thousand, forty-one".
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