Base | Representation |
---|---|
bin | 100110101111001100111… |
… | …0000000101111111011001 |
3 | 200211222021210001222012210 |
4 | 1031132121300011333121 |
5 | 1144212120231014431 |
6 | 15153455420025333 |
7 | 1056435526216500 |
oct | 115363160057731 |
9 | 20758253058183 |
10 | 5324044001241 |
11 | 1772a0704a869 |
12 | 71ba03692249 |
13 | 2c8094357034 |
14 | 145983cd9837 |
15 | 93755bb3d46 |
hex | 4d799c05fd9 |
5324044001241 has 24 divisors (see below), whose sum is σ = 8616731379264. Its totient is φ = 2910036470880.
The previous prime is 5324044001209. The next prime is 5324044001347. The reversal of 5324044001241 is 1421004404235.
It is not a de Polignac number, because 5324044001241 - 25 = 5324044001209 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 5324044001199 and 5324044001208.
It is not an unprimeable number, because it can be changed into a prime (5324044201241) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 787344150 + ... + 787350911.
It is an arithmetic number, because the mean of its divisors is an integer number (359030474136).
Almost surely, 25324044001241 is an apocalyptic number.
It is an amenable number.
5324044001241 is a deficient number, since it is larger than the sum of its proper divisors (3292687378023).
5324044001241 is a wasteful number, since it uses less digits than its factorization.
5324044001241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1574695101 (or 1574695094 counting only the distinct ones).
The product of its (nonzero) digits is 15360, while the sum is 30.
Adding to 5324044001241 its reverse (1421004404235), we get a palindrome (6745048405476).
The spelling of 5324044001241 in words is "five trillion, three hundred twenty-four billion, forty-four million, one thousand, two hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •