Base | Representation |
---|---|
bin | 11000001101100010001000… |
… | …00000010011101011110111 |
3 | 20222111211202112210000001222 |
4 | 30012301010000103223313 |
5 | 23434302201204020120 |
6 | 305122455530140555 |
7 | 14133401244010256 |
oct | 1406610400235367 |
9 | 228454675700058 |
10 | 53241555532535 |
11 | 15a67687103687 |
12 | 5b7a6a128175b |
13 | 239287098b246 |
14 | d20c955ca79d |
15 | 624e05b78525 |
hex | 306c44013af7 |
53241555532535 has 8 divisors (see below), whose sum is σ = 66667686927840. Its totient is φ = 40741364233504.
The previous prime is 53241555532531. The next prime is 53241555532553. The reversal of 53241555532535 is 53523555514235.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53241555532535 - 22 = 53241555532531 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53241555532531) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 231485023940 + ... + 231485024169.
It is an arithmetic number, because the mean of its divisors is an integer number (8333460865980).
Almost surely, 253241555532535 is an apocalyptic number.
53241555532535 is a deficient number, since it is larger than the sum of its proper divisors (13426131395305).
53241555532535 is a wasteful number, since it uses less digits than its factorization.
53241555532535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 462970048137.
The product of its digits is 33750000, while the sum is 53.
The spelling of 53241555532535 in words is "fifty-three trillion, two hundred forty-one billion, five hundred fifty-five million, five hundred thirty-two thousand, five hundred thirty-five".
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