Base | Representation |
---|---|
bin | 1111011111101110101… |
… | …00011101111001111011 |
3 | 1212220021222120102020011 |
4 | 13233313110131321323 |
5 | 32210404130041011 |
6 | 1044332313242351 |
7 | 53316056002141 |
oct | 7576724357173 |
9 | 1786258512204 |
10 | 532430315131 |
11 | 19589103a230 |
12 | 87231a033b7 |
13 | 3b291b84060 |
14 | 1baac33d591 |
15 | dcb2cc0621 |
hex | 7bf751de7b |
532430315131 has 64 divisors (see below), whose sum is σ = 652927242240. Its totient is φ = 427508928000.
The previous prime is 532430315101. The next prime is 532430315227. The reversal of 532430315131 is 131513034235.
It is a happy number.
It is not a de Polignac number, because 532430315131 - 231 = 530282831483 is a prime.
It is a super-2 number, since 2×5324303151312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 532430315093 and 532430315102.
It is not an unprimeable number, because it can be changed into a prime (532430315101) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 248449846 + ... + 248451988.
It is an arithmetic number, because the mean of its divisors is an integer number (10201988160).
Almost surely, 2532430315131 is an apocalyptic number.
532430315131 is a deficient number, since it is larger than the sum of its proper divisors (120496927109).
532430315131 is a wasteful number, since it uses less digits than its factorization.
532430315131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2708.
The product of its (nonzero) digits is 16200, while the sum is 31.
Adding to 532430315131 its reverse (131513034235), we get a palindrome (663943349366).
The spelling of 532430315131 in words is "five hundred thirty-two billion, four hundred thirty million, three hundred fifteen thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.086 sec. • engine limits •