Base | Representation |
---|---|
bin | 110001100101111011… |
… | …100010101110111011 |
3 | 12002110001201210201112 |
4 | 301211323202232323 |
5 | 1333023411341011 |
6 | 40243530110535 |
7 | 3563402052614 |
oct | 614573425673 |
9 | 162401653645 |
10 | 53249715131 |
11 | 20646092138 |
12 | a3a127b44b |
13 | 50380c70a2 |
14 | 281217ac0b |
15 | 15b9d1358b |
hex | c65ee2bbb |
53249715131 has 2 divisors, whose sum is σ = 53249715132. Its totient is φ = 53249715130.
The previous prime is 53249715119. The next prime is 53249715227. The reversal of 53249715131 is 13151794235.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53249715131 - 218 = 53249452987 is a prime.
It is a super-2 number, since 2×532497151312 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (53249715331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26624857565 + 26624857566.
It is an arithmetic number, because the mean of its divisors is an integer number (26624857566).
Almost surely, 253249715131 is an apocalyptic number.
53249715131 is a deficient number, since it is larger than the sum of its proper divisors (1).
53249715131 is an equidigital number, since it uses as much as digits as its factorization.
53249715131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 113400, while the sum is 41.
The spelling of 53249715131 in words is "fifty-three billion, two hundred forty-nine million, seven hundred fifteen thousand, one hundred thirty-one".
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