Base | Representation |
---|---|
bin | 110001100110000001… |
… | …110000101010001010 |
3 | 12002110011210121112022 |
4 | 301212001300222022 |
5 | 1333024321020114 |
6 | 40244025044442 |
7 | 3563421651536 |
oct | 614601605212 |
9 | 162404717468 |
10 | 53251345034 |
11 | 20646aa5768 |
12 | a3a1926722 |
13 | 5038547c24 |
14 | 2812482bc6 |
15 | 15ba03648e |
hex | c66070a8a |
53251345034 has 4 divisors (see below), whose sum is σ = 79877017554. Its totient is φ = 26625672516.
The previous prime is 53251345031. The next prime is 53251345099. The reversal of 53251345034 is 43054315235.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 43311853225 + 9939491809 = 208115^2 + 99697^2 .
It is a super-2 number, since 2×532513450342 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 53251344985 and 53251345003.
It is not an unprimeable number, because it can be changed into a prime (53251345031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13312836257 + ... + 13312836260.
Almost surely, 253251345034 is an apocalyptic number.
53251345034 is a deficient number, since it is larger than the sum of its proper divisors (26625672520).
53251345034 is a wasteful number, since it uses less digits than its factorization.
53251345034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26625672519.
The product of its (nonzero) digits is 108000, while the sum is 35.
The spelling of 53251345034 in words is "fifty-three billion, two hundred fifty-one million, three hundred forty-five thousand, thirty-four".
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