Base | Representation |
---|---|
bin | 100110101111110011110… |
… | …1010110111000100001001 |
3 | 200212002122212220012110012 |
4 | 1031133213222313010021 |
5 | 1144222304410032413 |
6 | 15154233235001305 |
7 | 1056513111530045 |
oct | 115374752670411 |
9 | 20762585805405 |
10 | 5325351252233 |
11 | 1773517a4a891 |
12 | 720109439235 |
13 | 2c824213052c |
14 | 145a69787025 |
15 | 937d08377a8 |
hex | 4d7e7ab7109 |
5325351252233 has 2 divisors, whose sum is σ = 5325351252234. Its totient is φ = 5325351252232.
The previous prime is 5325351252217. The next prime is 5325351252301. The reversal of 5325351252233 is 3322521535235.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5318060312464 + 7290939769 = 2306092^2 + 85387^2 .
It is a cyclic number.
It is not a de Polignac number, because 5325351252233 - 24 = 5325351252217 is a prime.
It is not a weakly prime, because it can be changed into another prime (5325351258233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2662675626116 + 2662675626117.
It is an arithmetic number, because the mean of its divisors is an integer number (2662675626117).
Almost surely, 25325351252233 is an apocalyptic number.
It is an amenable number.
5325351252233 is a deficient number, since it is larger than the sum of its proper divisors (1).
5325351252233 is an equidigital number, since it uses as much as digits as its factorization.
5325351252233 is an evil number, because the sum of its binary digits is even.
The product of its digits is 810000, while the sum is 41.
Adding to 5325351252233 its reverse (3322521535235), we get a palindrome (8647872787468).
The spelling of 5325351252233 in words is "five trillion, three hundred twenty-five billion, three hundred fifty-one million, two hundred fifty-two thousand, two hundred thirty-three".
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