Base | Representation |
---|---|
bin | 100110101111110011110… |
… | …1010110111000100011101 |
3 | 200212002122212220012110221 |
4 | 1031133213222313010131 |
5 | 1144222304410033003 |
6 | 15154233235001341 |
7 | 1056513111530104 |
oct | 115374752670435 |
9 | 20762585805427 |
10 | 5325351252253 |
11 | 1773517a4a8aa |
12 | 720109439251 |
13 | 2c8242130546 |
14 | 145a6978703b |
15 | 937d08377bd |
hex | 4d7e7ab711d |
5325351252253 has 4 divisors (see below), whose sum is σ = 5344168748128. Its totient is φ = 5306533756380.
The previous prime is 5325351252233. The next prime is 5325351252301. The reversal of 5325351252253 is 3522521535235.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5325351252253 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5325351252233) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9408747513 + ... + 9408748078.
It is an arithmetic number, because the mean of its divisors is an integer number (1336042187032).
Almost surely, 25325351252253 is an apocalyptic number.
It is an amenable number.
5325351252253 is a deficient number, since it is larger than the sum of its proper divisors (18817495875).
5325351252253 is a wasteful number, since it uses less digits than its factorization.
5325351252253 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18817495874.
The product of its digits is 1350000, while the sum is 43.
Adding to 5325351252253 its reverse (3522521535235), we get a palindrome (8847872787488).
The spelling of 5325351252253 in words is "five trillion, three hundred twenty-five billion, three hundred fifty-one million, two hundred fifty-two thousand, two hundred fifty-three".
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