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5325351252397 = 111925480149533
BaseRepresentation
bin100110101111110011110…
…1010110111000110101101
3200212002122212220012200021
41031133213222313012231
51144222304410034042
615154233235002141
71056513111530401
oct115374752670655
920762585805607
105325351252397
111773517a4aa20
12720109439351
132c8242130627
14145a69787101
15937d0837867
hex4d7e7ab71ad

5325351252397 has 8 divisors (see below), whose sum is σ = 6115235888160. Its totient is φ = 4586426915760.

The previous prime is 5325351252367. The next prime is 5325351252413. The reversal of 5325351252397 is 7932521535235.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5325351252397 is a prime.

It is a super-2 number, since 2×53253512523972 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5325351252367) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12740074558 + ... + 12740074975.

It is an arithmetic number, because the mean of its divisors is an integer number (764404486020).

Almost surely, 25325351252397 is an apocalyptic number.

It is an amenable number.

5325351252397 is a deficient number, since it is larger than the sum of its proper divisors (789884635763).

5325351252397 is a wasteful number, since it uses less digits than its factorization.

5325351252397 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25480149563.

The product of its digits is 8505000, while the sum is 52.

The spelling of 5325351252397 in words is "five trillion, three hundred twenty-five billion, three hundred fifty-one million, two hundred fifty-two thousand, three hundred ninety-seven".

Divisors: 1 11 19 209 25480149533 280281644863 484122841127 5325351252397