Search a number
-
+
5325351252367 is a prime number
BaseRepresentation
bin100110101111110011110…
…1010110111000110001111
3200212002122212220012122011
41031133213222313012033
51144222304410033432
615154233235002051
71056513111530326
oct115374752670617
920762585805564
105325351252367
111773517a4a9a3
12720109439327
132c8242130603
14145a697870bd
15937d0837847
hex4d7e7ab718f

5325351252367 has 2 divisors, whose sum is σ = 5325351252368. Its totient is φ = 5325351252366.

The previous prime is 5325351252301. The next prime is 5325351252413. The reversal of 5325351252367 is 7632521535235.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5325351252367 - 211 = 5325351250319 is a prime.

It is a super-2 number, since 2×53253512523672 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 5325351252367.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5325351252167) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2662675626183 + 2662675626184.

It is an arithmetic number, because the mean of its divisors is an integer number (2662675626184).

Almost surely, 25325351252367 is an apocalyptic number.

5325351252367 is a deficient number, since it is larger than the sum of its proper divisors (1).

5325351252367 is an equidigital number, since it uses as much as digits as its factorization.

5325351252367 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5670000, while the sum is 49.

The spelling of 5325351252367 in words is "five trillion, three hundred twenty-five billion, three hundred fifty-one million, two hundred fifty-two thousand, three hundred sixty-seven".