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53254055223245 = 510650811044649
BaseRepresentation
bin11000001101111001011010…
…00010110101111111001101
320222120001000200011002012202
430012330231002311333031
523440003301114120440
6305132324130011245
714134323063432242
oct1406745502657715
9228501020132182
1053254055223245
1115a71a10930288
125b80bab416b25
132393ab34ca136
14d2171d71d5c9
156253d8200615
hex306f2d0b5fcd

53254055223245 has 4 divisors (see below), whose sum is σ = 63904866267900. Its totient is φ = 42603244178592.

The previous prime is 53254055223179. The next prime is 53254055223277. The reversal of 53254055223245 is 54232255045235.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 12469917250729 + 40784137972516 = 3531277^2 + 6386246^2 .

It is a cyclic number.

It is not a de Polignac number, because 53254055223245 - 226 = 53253988114381 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 53254055223245.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5325405522320 + ... + 5325405522329.

It is an arithmetic number, because the mean of its divisors is an integer number (15976216566975).

Almost surely, 253254055223245 is an apocalyptic number.

It is an amenable number.

53254055223245 is a deficient number, since it is larger than the sum of its proper divisors (10650811044655).

53254055223245 is a wasteful number, since it uses less digits than its factorization.

53254055223245 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10650811044654.

The product of its (nonzero) digits is 7200000, while the sum is 47.

The spelling of 53254055223245 in words is "fifty-three trillion, two hundred fifty-four billion, fifty-five million, two hundred twenty-three thousand, two hundred forty-five".

Divisors: 1 5 10650811044649 53254055223245