Base | Representation |
---|---|
bin | 110001100110110010… |
… | …110101100001111101 |
3 | 12002111002000020000012 |
4 | 301212302311201331 |
5 | 1333041114210140 |
6 | 40245204513005 |
7 | 3563636213054 |
oct | 614662654175 |
9 | 162432006005 |
10 | 53264210045 |
11 | 20653292402 |
12 | a3a60ab765 |
13 | 503b100867 |
14 | 281407139b |
15 | 15bb228265 |
hex | c66cb587d |
53264210045 has 4 divisors (see below), whose sum is σ = 63917052060. Its totient is φ = 42611368032.
The previous prime is 53264210023. The next prime is 53264210057. The reversal of 53264210045 is 54001246235.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 12118927396 + 41145282649 = 110086^2 + 202843^2 .
It is a cyclic number.
It is not a de Polignac number, because 53264210045 - 212 = 53264205949 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 53264209993 and 53264210020.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5326421000 + ... + 5326421009.
It is an arithmetic number, because the mean of its divisors is an integer number (15979263015).
Almost surely, 253264210045 is an apocalyptic number.
It is an amenable number.
53264210045 is a deficient number, since it is larger than the sum of its proper divisors (10652842015).
53264210045 is a wasteful number, since it uses less digits than its factorization.
53264210045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10652842014.
The product of its (nonzero) digits is 28800, while the sum is 32.
The spelling of 53264210045 in words is "fifty-three billion, two hundred sixty-four million, two hundred ten thousand, forty-five".
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