Base | Representation |
---|---|
bin | 100110110001000011101… |
… | …0111011000011010010111 |
3 | 200212100120121101010010121 |
4 | 1031202013113120122113 |
5 | 1144243301302004003 |
6 | 15155355144332411 |
7 | 1056636364003354 |
oct | 115420727303227 |
9 | 20770517333117 |
10 | 5328030500503 |
11 | 1774672352757 |
12 | 720736774107 |
13 | 2c857b22c639 |
14 | 145c4153762b |
15 | 938dab6dcbd |
hex | 4d8875d8697 |
5328030500503 has 8 divisors (see below), whose sum is σ = 5399653326080. Its totient is φ = 5256512160120.
The previous prime is 5328030500489. The next prime is 5328030500579. The reversal of 5328030500503 is 3050050308235.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5328030500503 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5328030500203) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 26018625 + ... + 26222602.
It is an arithmetic number, because the mean of its divisors is an integer number (674956665760).
Almost surely, 25328030500503 is an apocalyptic number.
5328030500503 is a deficient number, since it is larger than the sum of its proper divisors (71622825577).
5328030500503 is a wasteful number, since it uses less digits than its factorization.
5328030500503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52242597.
The product of its (nonzero) digits is 54000, while the sum is 34.
Adding to 5328030500503 its reverse (3050050308235), we get a palindrome (8378080808738).
The spelling of 5328030500503 in words is "five trillion, three hundred twenty-eight billion, thirty million, five hundred thousand, five hundred three".
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