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5328253 = 7761179
BaseRepresentation
bin10100010100110101111101
3101000200222201
4110110311331
52331001003
6310111501
763201160
oct24246575
911020881
105328253
11300a217
12194b591
131147318
149c9ad7
15703b1d
hex514d7d

5328253 has 4 divisors (see below), whose sum is σ = 6089440. Its totient is φ = 4567068.

The previous prime is 5328251. The next prime is 5328263. The reversal of 5328253 is 3528235.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5328253 - 21 = 5328251 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5328251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 380583 + ... + 380596.

It is an arithmetic number, because the mean of its divisors is an integer number (1522360).

Almost surely, 25328253 is an apocalyptic number.

It is an amenable number.

5328253 is a deficient number, since it is larger than the sum of its proper divisors (761187).

5328253 is an equidigital number, since it uses as much as digits as its factorization.

5328253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 761186.

The product of its digits is 7200, while the sum is 28.

The square root of 5328253 is about 2308.3008902654. The cubic root of 5328253 is about 174.6605993237.

It can be divided in two parts, 53282 and 53, that added together give a palindrome (53335).

The spelling of 5328253 in words is "five million, three hundred twenty-eight thousand, two hundred fifty-three".

Divisors: 1 7 761179 5328253