Base | Representation |
---|---|
bin | 100110110001110101000… |
… | …1111111000000000000001 |
3 | 200212111212020000212020001 |
4 | 1031203222033320000001 |
5 | 1144310201001231441 |
6 | 15200231530120001 |
7 | 1060025450036032 |
oct | 115435217700001 |
9 | 20774766025201 |
10 | 5329689477121 |
11 | 1775343846409 |
12 | 720b1a280001 |
13 | 2c8783b445c9 |
14 | 145d5b9c0a89 |
15 | 9398661c731 |
hex | 4d8ea3f8001 |
5329689477121 has 4 divisors (see below), whose sum is σ = 5643200622852. Its totient is φ = 5016178331392.
The previous prime is 5329689477071. The next prime is 5329689477131. The reversal of 5329689477121 is 1217749869235.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1978062222096 + 3351627255025 = 1406436^2 + 1830745^2 .
It is a cyclic number.
It is not a de Polignac number, because 5329689477121 - 221 = 5329687379969 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5329689477131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 156755572840 + ... + 156755572873.
It is an arithmetic number, because the mean of its divisors is an integer number (1410800155713).
Almost surely, 25329689477121 is an apocalyptic number.
It is an amenable number.
5329689477121 is a deficient number, since it is larger than the sum of its proper divisors (313511145731).
5329689477121 is a wasteful number, since it uses less digits than its factorization.
5329689477121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 313511145730.
The product of its digits is 45722880, while the sum is 64.
The spelling of 5329689477121 in words is "five trillion, three hundred twenty-nine billion, six hundred eighty-nine million, four hundred seventy-seven thousand, one hundred twenty-one".
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