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5329689477121 = 17313511145713
BaseRepresentation
bin100110110001110101000…
…1111111000000000000001
3200212111212020000212020001
41031203222033320000001
51144310201001231441
615200231530120001
71060025450036032
oct115435217700001
920774766025201
105329689477121
111775343846409
12720b1a280001
132c8783b445c9
14145d5b9c0a89
159398661c731
hex4d8ea3f8001

5329689477121 has 4 divisors (see below), whose sum is σ = 5643200622852. Its totient is φ = 5016178331392.

The previous prime is 5329689477071. The next prime is 5329689477131. The reversal of 5329689477121 is 1217749869235.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1978062222096 + 3351627255025 = 1406436^2 + 1830745^2 .

It is a cyclic number.

It is not a de Polignac number, because 5329689477121 - 221 = 5329687379969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5329689477131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 156755572840 + ... + 156755572873.

It is an arithmetic number, because the mean of its divisors is an integer number (1410800155713).

Almost surely, 25329689477121 is an apocalyptic number.

It is an amenable number.

5329689477121 is a deficient number, since it is larger than the sum of its proper divisors (313511145731).

5329689477121 is a wasteful number, since it uses less digits than its factorization.

5329689477121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 313511145730.

The product of its digits is 45722880, while the sum is 64.

The spelling of 5329689477121 in words is "five trillion, three hundred twenty-nine billion, six hundred eighty-nine million, four hundred seventy-seven thousand, one hundred twenty-one".

Divisors: 1 17 313511145713 5329689477121