Base | Representation |
---|---|
bin | 100110110001110101000… |
… | …1111111000000000001011 |
3 | 200212111212020000212020102 |
4 | 1031203222033320000023 |
5 | 1144310201001232011 |
6 | 15200231530120015 |
7 | 1060025450036045 |
oct | 115435217700013 |
9 | 20774766025212 |
10 | 5329689477131 |
11 | 1775343846418 |
12 | 720b1a28000b |
13 | 2c8783b44606 |
14 | 145d5b9c0a95 |
15 | 9398661c73b |
hex | 4d8ea3f800b |
5329689477131 has 2 divisors, whose sum is σ = 5329689477132. Its totient is φ = 5329689477130.
The previous prime is 5329689477071. The next prime is 5329689477137. The reversal of 5329689477131 is 1317749869235.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5329689477131 - 26 = 5329689477067 is a prime.
It is a super-2 number, since 2×53296894771312 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5329689477137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2664844738565 + 2664844738566.
It is an arithmetic number, because the mean of its divisors is an integer number (2664844738566).
Almost surely, 25329689477131 is an apocalyptic number.
5329689477131 is a deficient number, since it is larger than the sum of its proper divisors (1).
5329689477131 is an equidigital number, since it uses as much as digits as its factorization.
5329689477131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 68584320, while the sum is 65.
The spelling of 5329689477131 in words is "five trillion, three hundred twenty-nine billion, six hundred eighty-nine million, four hundred seventy-seven thousand, one hundred thirty-one".
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