Base | Representation |
---|---|
bin | 110001101000111100… |
… | …101000001110101011 |
3 | 12002120120222101020110 |
4 | 301220330220032223 |
5 | 1333124341101220 |
6 | 40252535025403 |
7 | 3564555225201 |
oct | 615074501653 |
9 | 162516871213 |
10 | 53300331435 |
11 | 2067171399a |
12 | a3b620b263 |
13 | 5045739b70 |
14 | 2818b95071 |
15 | 15be4b0be0 |
hex | c68f283ab |
53300331435 has 48 divisors (see below), whose sum is σ = 93836959776. Its totient is φ = 25681654272.
The previous prime is 53300331433. The next prime is 53300331451. The reversal of 53300331435 is 53413300335.
53300331435 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 53300331435 - 21 = 53300331433 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53300331433) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 368887 + ... + 492623.
It is an arithmetic number, because the mean of its divisors is an integer number (1954936662).
Almost surely, 253300331435 is an apocalyptic number.
53300331435 is a deficient number, since it is larger than the sum of its proper divisors (40536628341).
53300331435 is a wasteful number, since it uses less digits than its factorization.
53300331435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 123852 (or 123805 counting only the distinct ones).
The product of its (nonzero) digits is 24300, while the sum is 30.
The spelling of 53300331435 in words is "fifty-three billion, three hundred million, three hundred thirty-one thousand, four hundred thirty-five".
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