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53303010153 = 3194719896607
BaseRepresentation
bin110001101001000110…
…110110001101101001
312002120210000110202020
4301221012312031221
51333131032311103
640253112255053
73564620052651
oct615106661551
9162523013666
1053303010153
1120673183508
12a3b70a1489
1350461671c3
142819291361
1515be83e753
hexc691b6369

53303010153 has 16 divisors (see below), whose sum is σ = 76402974720. Its totient is φ = 32948779536.

The previous prime is 53303010151. The next prime is 53303010181. The reversal of 53303010153 is 35101030335.

53303010153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 53303010153 - 21 = 53303010151 is a prime.

It is not an unprimeable number, because it can be changed into a prime (53303010151) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9945625 + ... + 9950982.

It is an arithmetic number, because the mean of its divisors is an integer number (4775185920).

Almost surely, 253303010153 is an apocalyptic number.

It is an amenable number.

53303010153 is a deficient number, since it is larger than the sum of its proper divisors (23099964567).

53303010153 is a wasteful number, since it uses less digits than its factorization.

53303010153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19896676.

The product of its (nonzero) digits is 2025, while the sum is 24.

Adding to 53303010153 its reverse (35101030335), we get a palindrome (88404040488).

The spelling of 53303010153 in words is "fifty-three billion, three hundred three million, ten thousand, one hundred fifty-three".

Divisors: 1 3 19 47 57 141 893 2679 19896607 59689821 378035533 935140529 1134106599 2805421587 17767670051 53303010153