Base | Representation |
---|---|
bin | 110001101001000110… |
… | …110110001101101001 |
3 | 12002120210000110202020 |
4 | 301221012312031221 |
5 | 1333131032311103 |
6 | 40253112255053 |
7 | 3564620052651 |
oct | 615106661551 |
9 | 162523013666 |
10 | 53303010153 |
11 | 20673183508 |
12 | a3b70a1489 |
13 | 50461671c3 |
14 | 2819291361 |
15 | 15be83e753 |
hex | c691b6369 |
53303010153 has 16 divisors (see below), whose sum is σ = 76402974720. Its totient is φ = 32948779536.
The previous prime is 53303010151. The next prime is 53303010181. The reversal of 53303010153 is 35101030335.
53303010153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 53303010153 - 21 = 53303010151 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53303010151) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9945625 + ... + 9950982.
It is an arithmetic number, because the mean of its divisors is an integer number (4775185920).
Almost surely, 253303010153 is an apocalyptic number.
It is an amenable number.
53303010153 is a deficient number, since it is larger than the sum of its proper divisors (23099964567).
53303010153 is a wasteful number, since it uses less digits than its factorization.
53303010153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19896676.
The product of its (nonzero) digits is 2025, while the sum is 24.
Adding to 53303010153 its reverse (35101030335), we get a palindrome (88404040488).
The spelling of 53303010153 in words is "fifty-three billion, three hundred three million, ten thousand, one hundred fifty-three".
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