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53304162465193 is a prime number
BaseRepresentation
bin11000001111010110101111…
…01010110011010110101001
320222201211100201202201010121
430013223113222303112221
523441313411042341233
6305211332202043241
714141045560111603
oct1407532752632651
9228654321681117
1053304162465193
1115a91194090842
125b8a8541a9521
13239873a547a23
14d23d143a8173
1562686c1ca92d
hex307ad7ab35a9

53304162465193 has 2 divisors, whose sum is σ = 53304162465194. Its totient is φ = 53304162465192.

The previous prime is 53304162465179. The next prime is 53304162465221. The reversal of 53304162465193 is 39156426140335.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 31873160679424 + 21431001785769 = 5645632^2 + 4629363^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53304162465193 is a prime.

It is a super-2 number, since 2×533041624651932 (a number of 28 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 53304162465193.

It is not a weakly prime, because it can be changed into another prime (53304162465143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26652081232596 + 26652081232597.

It is an arithmetic number, because the mean of its divisors is an integer number (26652081232597).

Almost surely, 253304162465193 is an apocalyptic number.

It is an amenable number.

53304162465193 is a deficient number, since it is larger than the sum of its proper divisors (1).

53304162465193 is an equidigital number, since it uses as much as digits as its factorization.

53304162465193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6998400, while the sum is 52.

The spelling of 53304162465193 in words is "fifty-three trillion, three hundred four billion, one hundred sixty-two million, four hundred sixty-five thousand, one hundred ninety-three".