Base | Representation |
---|---|
bin | 11000001111011001010101… |
… | …00100001010000110101100 |
3 | 20222201221221122201222221110 |
4 | 30013230222210022012230 |
5 | 23441324233111413200 |
6 | 305212122203032020 |
7 | 14141125205331315 |
oct | 1407545244120654 |
9 | 228657848658843 |
10 | 53305553232300 |
11 | 15a91838143746 |
12 | 5b8ab81b0b610 |
13 | 23988cc712b45 |
14 | d24006d9560c |
15 | 6268ee349b50 |
hex | 307b2a90a1ac |
53305553232300 has 288 divisors, whose sum is σ = 160205937011008. Its totient is φ = 13673179054080.
The previous prime is 53305553232299. The next prime is 53305553232353. The reversal of 53305553232300 is 323235550335.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1008841482 + ... + 1008894318.
Almost surely, 253305553232300 is an apocalyptic number.
53305553232300 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 53305553232300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (80102968505504).
53305553232300 is an abundant number, since it is smaller than the sum of its proper divisors (106900383778708).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53305553232300 is a wasteful number, since it uses less digits than its factorization.
53305553232300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 53925 (or 53918 counting only the distinct ones).
The product of its (nonzero) digits is 607500, while the sum is 39.
Adding to 53305553232300 its reverse (323235550335), we get a palindrome (53628788782635).
The spelling of 53305553232300 in words is "fifty-three trillion, three hundred five billion, five hundred fifty-three million, two hundred thirty-two thousand, three hundred".
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