Base | Representation |
---|---|
bin | 110001101001100001… |
… | …100100000000001011 |
3 | 12002121021012021110122 |
4 | 301221201210000023 |
5 | 1333134330412301 |
6 | 40253522333455 |
7 | 3565033431512 |
oct | 615141440013 |
9 | 162537167418 |
10 | 53310013451 |
11 | 20677127162 |
12 | a3b94ba28b |
13 | 5047749a76 |
14 | 281a195679 |
15 | 15c027481b |
hex | c6986400b |
53310013451 has 2 divisors, whose sum is σ = 53310013452. Its totient is φ = 53310013450.
The previous prime is 53310013409. The next prime is 53310013511. The reversal of 53310013451 is 15431001335.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53310013451 - 214 = 53309997067 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 53310013451.
It is not a weakly prime, because it can be changed into another prime (53310013651) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26655006725 + 26655006726.
It is an arithmetic number, because the mean of its divisors is an integer number (26655006726).
Almost surely, 253310013451 is an apocalyptic number.
53310013451 is a deficient number, since it is larger than the sum of its proper divisors (1).
53310013451 is an equidigital number, since it uses as much as digits as its factorization.
53310013451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2700, while the sum is 26.
Adding to 53310013451 its reverse (15431001335), we get a palindrome (68741014786).
The spelling of 53310013451 in words is "fifty-three billion, three hundred ten million, thirteen thousand, four hundred fifty-one".
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