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53311330254601 is a prime number
BaseRepresentation
bin11000001111100100000101…
…11001101111111100001001
320222202111212021020010201101
430013302002321233330021
523441423101021121401
6305214515332421401
714141421314242036
oct1407620271577411
9228674767203641
1053311330254601
1115a94232118041
125b90114777861
13239931053aa33
14d243d432038d
15626b3b5da101
hex307c82e6ff09

53311330254601 has 2 divisors, whose sum is σ = 53311330254602. Its totient is φ = 53311330254600.

The previous prime is 53311330254529. The next prime is 53311330254647. The reversal of 53311330254601 is 10645203311335.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 44003003842576 + 9308326412025 = 6633476^2 + 3050955^2 .

It is a cyclic number.

It is not a de Polignac number, because 53311330254601 - 211 = 53311330252553 is a prime.

It is a super-3 number, since 3×533113302546013 (a number of 42 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (53311330254401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26655665127300 + 26655665127301.

It is an arithmetic number, because the mean of its divisors is an integer number (26655665127301).

Almost surely, 253311330254601 is an apocalyptic number.

It is an amenable number.

53311330254601 is a deficient number, since it is larger than the sum of its proper divisors (1).

53311330254601 is an equidigital number, since it uses as much as digits as its factorization.

53311330254601 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 97200, while the sum is 37.

Adding to 53311330254601 its reverse (10645203311335), we get a palindrome (63956533565936).

The spelling of 53311330254601 in words is "fifty-three trillion, three hundred eleven billion, three hundred thirty million, two hundred fifty-four thousand, six hundred one".