53314000041335 has 8 divisors (see below), whose sum is σ = 69792872781456. Its totient is φ = 38773818211840.

The previous prime is 53314000041307. The next prime is 53314000041349.

53314000041335 is nontrivially palindromic in base 10.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 53314000041335 - 2¹⁴ = 53314000024951 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 484672727594 + ... + 484672727703.

It is an arithmetic number, because the mean of its divisors is an integer number (8724109097682).

Almost surely, 2^{53314000041335} is an apocalyptic number.

53314000041335 is a gapful number since it is divisible by the number (55) formed by its first and last digit.

53314000041335 is a deficient number, since it is larger than the sum of its proper divisors (16478872740121).

53314000041335 is a wasteful number, since it uses less digits than its factorization.

53314000041335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 969345455313.

The product of its (nonzero) digits is 32400, while the sum is 32.

It can be divided in two parts, 533140000 and 41335, that added together give a palindrome (533181335).

The spelling of 53314000041335 in words is "fifty-three trillion, three hundred fourteen billion, forty-one thousand, three hundred thirty-five".