Base | Representation |
---|---|
bin | 100110110010101001010… |
… | …0111001010001010100110 |
3 | 200212200101020201112101011 |
4 | 1031211102213022022212 |
5 | 1144322242221130202 |
6 | 15201121354452434 |
7 | 1060120030526305 |
oct | 115452247121246 |
9 | 20780336645334 |
10 | 5331440411302 |
11 | 1776062138155 |
12 | 72132873411a |
13 | 2c89a2815535 |
14 | 14608636443c |
15 | 93a3a1d2bd7 |
hex | 4d9529ca2a6 |
5331440411302 has 4 divisors (see below), whose sum is σ = 7997160616956. Its totient is φ = 2665720205650.
The previous prime is 5331440411203. The next prime is 5331440411359. The reversal of 5331440411302 is 2031140441335.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1332860102824 + ... + 1332860102827.
It is an arithmetic number, because the mean of its divisors is an integer number (1999290154239).
Almost surely, 25331440411302 is an apocalyptic number.
5331440411302 is a deficient number, since it is larger than the sum of its proper divisors (2665720205654).
5331440411302 is a wasteful number, since it uses less digits than its factorization.
5331440411302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2665720205653.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 5331440411302 its reverse (2031140441335), we get a palindrome (7362580852637).
The spelling of 5331440411302 in words is "five trillion, three hundred thirty-one billion, four hundred forty million, four hundred eleven thousand, three hundred two".
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