Base | Representation |
---|---|
bin | 100110110010111011100… |
… | …1001001100101111000111 |
3 | 200212201221222000020111201 |
4 | 1031211313021030233013 |
5 | 1144330021122031003 |
6 | 15201302251243331 |
7 | 1060141152236146 |
oct | 115456711145707 |
9 | 20781858006451 |
10 | 5332053314503 |
11 | 17763470a9423 |
12 | 721479a49547 |
13 | 2c8a6c7ab256 |
14 | 14610390975d |
15 | 93a73dedb1d |
hex | 4d97724cbc7 |
5332053314503 has 8 divisors (see below), whose sum is σ = 5404016730672. Its totient is φ = 5260436710656.
The previous prime is 5332053314479. The next prime is 5332053314519. The reversal of 5332053314503 is 3054133502335.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5332053314503 - 213 = 5332053306311 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5332053314593) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 86672125 + ... + 86733622.
It is an arithmetic number, because the mean of its divisors is an integer number (675502091334).
Almost surely, 25332053314503 is an apocalyptic number.
5332053314503 is a deficient number, since it is larger than the sum of its proper divisors (71963416169).
5332053314503 is a wasteful number, since it uses less digits than its factorization.
5332053314503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 173406161.
The product of its (nonzero) digits is 243000, while the sum is 37.
Adding to 5332053314503 its reverse (3054133502335), we get a palindrome (8386186816838).
The spelling of 5332053314503 in words is "five trillion, three hundred thirty-two billion, fifty-three million, three hundred fourteen thousand, five hundred three".
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