Base | Representation |
---|---|
bin | 100110110011011111001… |
… | …0000110110010011000011 |
3 | 200212212001010012110011022 |
4 | 1031212332100312103003 |
5 | 1144334442101031313 |
6 | 15202020513340055 |
7 | 1060212551202143 |
oct | 115467620662303 |
9 | 20785033173138 |
10 | 5333246502083 |
11 | 17768a9681965 |
12 | 72175156762b |
13 | 2c8bcca589c6 |
14 | 1461b8184923 |
15 | 93ae3a40c08 |
hex | 4d9be4364c3 |
5333246502083 has 2 divisors, whose sum is σ = 5333246502084. Its totient is φ = 5333246502082.
The previous prime is 5333246502049. The next prime is 5333246502097. The reversal of 5333246502083 is 3802056423335.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5333246502083 - 210 = 5333246501059 is a prime.
It is not a weakly prime, because it can be changed into another prime (5333246502383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2666623251041 + 2666623251042.
It is an arithmetic number, because the mean of its divisors is an integer number (2666623251042).
Almost surely, 25333246502083 is an apocalyptic number.
5333246502083 is a deficient number, since it is larger than the sum of its proper divisors (1).
5333246502083 is an equidigital number, since it uses as much as digits as its factorization.
5333246502083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1555200, while the sum is 44.
The spelling of 5333246502083 in words is "five trillion, three hundred thirty-three billion, two hundred forty-six million, five hundred two thousand, eighty-three".
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