Base | Representation |
---|---|
bin | 11000010000100011000011… |
… | …01101100101000000011111 |
3 | 20222212202010001100100210210 |
4 | 30020101201231211000133 |
5 | 23443001313041414320 |
6 | 305242225454103503 |
7 | 14144026062165111 |
oct | 1410214155450037 |
9 | 228782101310723 |
10 | 53345133154335 |
11 | 15aa75a8a62a10 |
12 | 5b967891aab93 |
13 | 239c569744059 |
14 | d25cbd8533b1 |
15 | 6279690040e0 |
hex | 308461b6501f |
53345133154335 has 16 divisors (see below), whose sum is σ = 93111505142400. Its totient is φ = 25864306983840.
The previous prime is 53345133154307. The next prime is 53345133154373.
It is a happy number.
53345133154335 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 53345133154335 - 214 = 53345133137951 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 161651918485 + ... + 161651918814.
It is an arithmetic number, because the mean of its divisors is an integer number (5819469071400).
Almost surely, 253345133154335 is an apocalyptic number.
53345133154335 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53345133154335 is a deficient number, since it is larger than the sum of its proper divisors (39766371988065).
53345133154335 is a wasteful number, since it uses less digits than its factorization.
53345133154335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 323303837318.
The product of its digits is 7290000, while the sum is 48.
It can be divided in two parts, 5334513 and 3154335, that added together give a palindrome (8488848).
The spelling of 53345133154335 in words is "fifty-three trillion, three hundred forty-five billion, one hundred thirty-three million, one hundred fifty-four thousand, three hundred thirty-five".
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