Base | Representation |
---|---|
bin | 100110110100000101000… |
… | …1110110011000100110011 |
3 | 200212222022221110022220111 |
4 | 1031220022032303010303 |
5 | 1144400044341024021 |
6 | 15202351203122151 |
7 | 1060256255424562 |
oct | 115501216630463 |
9 | 20788287408814 |
10 | 5334521033011 |
11 | 17773a3063905 |
12 | 721a48373357 |
13 | 2c9073b17111 |
14 | 146299555bd9 |
15 | 93b6a89e8e1 |
hex | 4da0a3b3133 |
5334521033011 has 32 divisors (see below), whose sum is σ = 5795333913600. Its totient is φ = 4891712947200.
The previous prime is 5334521032963. The next prime is 5334521033027. The reversal of 5334521033011 is 1103301254335.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 5334521033011 - 217 = 5334520901939 is a prime.
It is a super-2 number, since 2×53345210330112 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5334521033071) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 66447751 + ... + 66527983.
It is an arithmetic number, because the mean of its divisors is an integer number (181104184800).
Almost surely, 25334521033011 is an apocalyptic number.
5334521033011 is a deficient number, since it is larger than the sum of its proper divisors (460812880589).
5334521033011 is a wasteful number, since it uses less digits than its factorization.
5334521033011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 80899.
The product of its (nonzero) digits is 16200, while the sum is 31.
Adding to 5334521033011 its reverse (1103301254335), we get a palindrome (6437822287346).
The spelling of 5334521033011 in words is "five trillion, three hundred thirty-four billion, five hundred twenty-one million, thirty-three thousand, eleven".
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