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5334525340531 is a prime number
BaseRepresentation
bin100110110100000101001…
…1111001110101101110011
3200212222100020120011201021
41031220022133032231303
51144400101441344111
615202351435320311
71060256340145132
oct115501237165563
920788306504637
105334525340531
1117773a5536142
12721a498b0097
132c907499494a
14146299d57919
1593b6ae50d71
hex4da0a7ceb73

5334525340531 has 2 divisors, whose sum is σ = 5334525340532. Its totient is φ = 5334525340530.

The previous prime is 5334525340499. The next prime is 5334525340537. The reversal of 5334525340531 is 1350435254335.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5334525340531 - 25 = 5334525340499 is a prime.

It is a super-3 number, since 3×53345253405313 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (5334525340537) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2667262670265 + 2667262670266.

It is an arithmetic number, because the mean of its divisors is an integer number (2667262670266).

Almost surely, 25334525340531 is an apocalyptic number.

5334525340531 is a deficient number, since it is larger than the sum of its proper divisors (1).

5334525340531 is an equidigital number, since it uses as much as digits as its factorization.

5334525340531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1620000, while the sum is 43.

The spelling of 5334525340531 in words is "five trillion, three hundred thirty-four billion, five hundred twenty-five million, three hundred forty thousand, five hundred thirty-one".