Base | Representation |
---|---|
bin | 100110110100000101001… |
… | …1111001110101101110011 |
3 | 200212222100020120011201021 |
4 | 1031220022133032231303 |
5 | 1144400101441344111 |
6 | 15202351435320311 |
7 | 1060256340145132 |
oct | 115501237165563 |
9 | 20788306504637 |
10 | 5334525340531 |
11 | 17773a5536142 |
12 | 721a498b0097 |
13 | 2c907499494a |
14 | 146299d57919 |
15 | 93b6ae50d71 |
hex | 4da0a7ceb73 |
5334525340531 has 2 divisors, whose sum is σ = 5334525340532. Its totient is φ = 5334525340530.
The previous prime is 5334525340499. The next prime is 5334525340537. The reversal of 5334525340531 is 1350435254335.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5334525340531 - 25 = 5334525340499 is a prime.
It is a super-3 number, since 3×53345253405313 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (5334525340537) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2667262670265 + 2667262670266.
It is an arithmetic number, because the mean of its divisors is an integer number (2667262670266).
Almost surely, 25334525340531 is an apocalyptic number.
5334525340531 is a deficient number, since it is larger than the sum of its proper divisors (1).
5334525340531 is an equidigital number, since it uses as much as digits as its factorization.
5334525340531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1620000, while the sum is 43.
The spelling of 5334525340531 in words is "five trillion, three hundred thirty-four billion, five hundred twenty-five million, three hundred forty thousand, five hundred thirty-one".
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