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5335003120049 is a prime number
BaseRepresentation
bin100110110100010011011…
…1101110100000110110001
3200220000120112120212222222
41031220212331310012301
51144402041244320144
615202511104010425
71060304231204261
oct115504675640661
920800515525888
105335003120049
1117776201a5a49
12721b61900a15
132c911c969a15
141463035a77a1
1593b97d7a2ee
hex4da26f741b1

5335003120049 has 2 divisors, whose sum is σ = 5335003120050. Its totient is φ = 5335003120048.

The previous prime is 5335003120037. The next prime is 5335003120103. The reversal of 5335003120049 is 9400213005335.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4905626968225 + 429376151824 = 2214865^2 + 655268^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5335003120049 is a prime.

It is not a weakly prime, because it can be changed into another prime (5335003120019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2667501560024 + 2667501560025.

It is an arithmetic number, because the mean of its divisors is an integer number (2667501560025).

Almost surely, 25335003120049 is an apocalyptic number.

It is an amenable number.

5335003120049 is a deficient number, since it is larger than the sum of its proper divisors (1).

5335003120049 is an equidigital number, since it uses as much as digits as its factorization.

5335003120049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48600, while the sum is 35.

The spelling of 5335003120049 in words is "five trillion, three hundred thirty-five billion, three million, one hundred twenty thousand, forty-nine".