Base | Representation |
---|---|
bin | 11000010000101110100101… |
… | …00111010110101001000111 |
3 | 20222220100002101100022120222 |
4 | 30020113102213112221013 |
5 | 23443102002003042320 |
6 | 305245131545214555 |
7 | 14144335334165222 |
oct | 1410272247265107 |
9 | 228810071308528 |
10 | 53351322315335 |
11 | 15aaa194643200 |
12 | 5b97a15a9145b |
13 | 23a0014a706b5 |
14 | d263098225b9 |
15 | 627bcc554825 |
hex | 3085d29d6a47 |
53351322315335 has 48 divisors (see below), whose sum is σ = 72429832110720. Its totient is φ = 37681778534400.
The previous prime is 53351322315329. The next prime is 53351322315337.
53351322315335 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 53351322315335 - 26 = 53351322315271 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53351322315337) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 6234122 + ... + 12065111.
It is an arithmetic number, because the mean of its divisors is an integer number (1508954835640).
Almost surely, 253351322315335 is an apocalyptic number.
53351322315335 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53351322315335 is a deficient number, since it is larger than the sum of its proper divisors (19078509795385).
53351322315335 is a wasteful number, since it uses less digits than its factorization.
53351322315335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18299400 (or 18299389 counting only the distinct ones).
The product of its digits is 1822500, while the sum is 44.
The spelling of 53351322315335 in words is "fifty-three trillion, three hundred fifty-one billion, three hundred twenty-two million, three hundred fifteen thousand, three hundred thirty-five".
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