53353000733 has 4 divisors (see below), whose sum is σ = 53408985948. Its totient is φ = 53297015520.

The previous prime is 53353000717. The next prime is 53353000793. The reversal of 53353000733 is 33700035335.

53353000733 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 14825984644 + 38527016089 = 121762^2 + 196283^2 .

It is a cyclic number.

It is not a de Polignac number, because 53353000733 - 2⁴ = 53353000717 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 53353000733.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53353000703) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27991178 + ... + 27993083.

It is an arithmetic number, because the mean of its divisors is an integer number (13352246487).

Almost surely, 2^53353000733 is an apocalyptic number.

It is an amenable number.

53353000733 is a deficient number, since it is larger than the sum of its proper divisors (55985215).

53353000733 is an equidigital number, since it uses as much as digits as its factorization.

53353000733 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55985214.

The product of its (nonzero) digits is 42525, while the sum is 32.

The spelling of 53353000733 in words is "fifty-three billion, three hundred fifty-three million, seven hundred thirty-three", and thus it is an aban number.