Base | Representation |
---|---|
bin | 110001101100000110… |
… | …101111011111111101 |
3 | 12002201021200012001211 |
4 | 301230012233133331 |
5 | 1333231422024201 |
6 | 40302110404421 |
7 | 3566100455200 |
oct | 615406573775 |
9 | 162637605054 |
10 | 53353314301 |
11 | 20699611791 |
12 | a40bb00711 |
13 | 50536cab81 |
14 | 2821c27937 |
15 | 15c3e79651 |
hex | c6c1af7fd |
53353314301 has 48 divisors (see below), whose sum is σ = 66830520960. Its totient is φ = 42314173440.
The previous prime is 53353314283. The next prime is 53353314307. The reversal of 53353314301 is 10341335335.
It is not a de Polignac number, because 53353314301 - 235 = 18993575933 is a prime.
It is a super-2 number, since 2×533533143012 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53353314307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 24779841 + ... + 24781993.
It is an arithmetic number, because the mean of its divisors is an integer number (1392302520).
Almost surely, 253353314301 is an apocalyptic number.
It is an amenable number.
53353314301 is a deficient number, since it is larger than the sum of its proper divisors (13477206659).
53353314301 is a wasteful number, since it uses less digits than its factorization.
53353314301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2674 (or 2667 counting only the distinct ones).
The product of its (nonzero) digits is 24300, while the sum is 31.
Adding to 53353314301 its reverse (10341335335), we get a palindrome (63694649636).
The spelling of 53353314301 in words is "fifty-three billion, three hundred fifty-three million, three hundred fourteen thousand, three hundred one".
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