Base | Representation |
---|---|
bin | 100110110100011101010… |
… | …1000101011110001110001 |
3 | 200220001102112112220000012 |
4 | 1031220322220223301301 |
5 | 1144403230240001413 |
6 | 15203003533104305 |
7 | 1060315346203436 |
oct | 115507250536161 |
9 | 20801375486005 |
10 | 5335333125233 |
11 | 177777a503801 |
12 | 722034328095 |
13 | 2c9173141c67 |
14 | 14633534bb8d |
15 | 93bb6d147a8 |
hex | 4da3aa2bc71 |
5335333125233 has 2 divisors, whose sum is σ = 5335333125234. Its totient is φ = 5335333125232.
The previous prime is 5335333125217. The next prime is 5335333125271. The reversal of 5335333125233 is 3325213335335.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4115088130624 + 1220244994609 = 2028568^2 + 1104647^2 .
It is a cyclic number.
It is not a de Polignac number, because 5335333125233 - 24 = 5335333125217 is a prime.
It is a super-2 number, since 2×53353331252332 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5335333185233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2667666562616 + 2667666562617.
It is an arithmetic number, because the mean of its divisors is an integer number (2667666562617).
Almost surely, 25335333125233 is an apocalyptic number.
It is an amenable number.
5335333125233 is a deficient number, since it is larger than the sum of its proper divisors (1).
5335333125233 is an equidigital number, since it uses as much as digits as its factorization.
5335333125233 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1093500, while the sum is 41.
The spelling of 5335333125233 in words is "five trillion, three hundred thirty-five billion, three hundred thirty-three million, one hundred twenty-five thousand, two hundred thirty-three".
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