5335341431143 has 4 divisors (see below), whose sum is σ = 5459419138888. Its totient is φ = 5211263723400.

The previous prime is 5335341431099. The next prime is 5335341431159. The reversal of 5335341431143 is 3411341435335.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5335341431143 - 2⁹ = 5335341430631 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5335341431096 and 5335341431105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5335341431543) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 62038853808 + ... + 62038853893.

It is an arithmetic number, because the mean of its divisors is an integer number (1364854784722).

Almost surely, 2^{5335341431143} is an apocalyptic number.

5335341431143 is a deficient number, since it is larger than the sum of its proper divisors (124077707745).

5335341431143 is a wasteful number, since it uses less digits than its factorization.

5335341431143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 124077707744.

The product of its digits is 388800, while the sum is 40.

Adding to 5335341431143 its reverse (3411341435335), we get a palindrome (8746682866478).

The spelling of 5335341431143 in words is "five trillion, three hundred thirty-five billion, three hundred forty-one million, four hundred thirty-one thousand, one hundred forty-three".