Base | Representation |
---|---|
bin | 100110110100011101100… |
… | …1000010111011101100111 |
3 | 200220001110010011211212112 |
4 | 1031220323020113131213 |
5 | 1144403234401240011 |
6 | 15203004431111235 |
7 | 1060315506614432 |
oct | 115507310273547 |
9 | 20801403154775 |
10 | 5335341430631 |
11 | 1777784166773 |
12 | 72203707251b |
13 | 2c9174a8c3b4 |
14 | 1463364b0819 |
15 | 93bb790558b |
hex | 4da3b217767 |
5335341430631 has 2 divisors, whose sum is σ = 5335341430632. Its totient is φ = 5335341430630.
The previous prime is 5335341430567. The next prime is 5335341430687. The reversal of 5335341430631 is 1360341435335.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5335341430631 - 26 = 5335341430567 is a prime.
It is a super-2 number, since 2×53353414306312 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5335341430831) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2667670715315 + 2667670715316.
It is an arithmetic number, because the mean of its divisors is an integer number (2667670715316).
Almost surely, 25335341430631 is an apocalyptic number.
5335341430631 is a deficient number, since it is larger than the sum of its proper divisors (1).
5335341430631 is an equidigital number, since it uses as much as digits as its factorization.
5335341430631 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 583200, while the sum is 41.
Adding to 5335341430631 its reverse (1360341435335), we get a palindrome (6695682865966).
The spelling of 5335341430631 in words is "five trillion, three hundred thirty-five billion, three hundred forty-one million, four hundred thirty thousand, six hundred thirty-one".
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