Base | Representation |
---|---|
bin | 100110110100011111011… |
… | …0111011100000111110110 |
3 | 200220001121111002220000022 |
4 | 1031220332313130013312 |
5 | 1144403401422232014 |
6 | 15203014550245142 |
7 | 1060320200406251 |
oct | 115507667340766 |
9 | 20801544086008 |
10 | 5335404102134 |
11 | 17778065817a7 |
12 | 7220540567b2 |
13 | 2c9184a63322 |
14 | 146340946098 |
15 | 93bbd184a8e |
hex | 4da3eddc1f6 |
5335404102134 has 16 divisors (see below), whose sum is σ = 8012442654720. Its totient is φ = 2664591407400.
The previous prime is 5335404102053. The next prime is 5335404102137. The reversal of 5335404102134 is 4312014045335.
It is a junction number, because it is equal to n+sod(n) for n = 5335404102094 and 5335404102103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5335404102137) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6663209 + ... + 7420859.
It is an arithmetic number, because the mean of its divisors is an integer number (500777665920).
Almost surely, 25335404102134 is an apocalyptic number.
5335404102134 is a deficient number, since it is larger than the sum of its proper divisors (2677038552586).
5335404102134 is a wasteful number, since it uses less digits than its factorization.
5335404102134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 761755.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 5335404102134 its reverse (4312014045335), we get a palindrome (9647418147469).
The spelling of 5335404102134 in words is "five trillion, three hundred thirty-five billion, four hundred four million, one hundred two thousand, one hundred thirty-four".
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