Base | Representation |
---|---|
bin | 100110110100011111011… |
… | …0111110100110010001111 |
3 | 200220001121111022000120200 |
4 | 1031220332313310302033 |
5 | 1144403401434000101 |
6 | 15203014552344543 |
7 | 1060320201306621 |
oct | 115507667646217 |
9 | 20801544260520 |
10 | 5335404203151 |
11 | 1777806640690 |
12 | 7220540a5153 |
13 | 2c9184a9a2b9 |
14 | 146340970c11 |
15 | 93bbd1a4986 |
hex | 4da3edf4c8f |
5335404203151 has 24 divisors (see below), whose sum is σ = 8408837788416. Its totient is φ = 3232988229840.
The previous prime is 5335404203141. The next prime is 5335404203189. The reversal of 5335404203151 is 1513024045335.
5335404203151 is a `hidden beast` number, since 5 + 3 + 35 + 404 + 203 + 15 + 1 = 666.
It is not a de Polignac number, because 5335404203151 - 217 = 5335404072079 is a prime.
It is a super-2 number, since 2×53354042031512 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5335404203111) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4371735 + ... + 5457368.
It is an arithmetic number, because the mean of its divisors is an integer number (350368241184).
Almost surely, 25335404203151 is an apocalyptic number.
5335404203151 is a deficient number, since it is larger than the sum of its proper divisors (3073433585265).
5335404203151 is a wasteful number, since it uses less digits than its factorization.
5335404203151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9834603 (or 9834600 counting only the distinct ones).
The product of its (nonzero) digits is 108000, while the sum is 36.
Adding to 5335404203151 its reverse (1513024045335), we get a palindrome (6848428248486).
The spelling of 5335404203151 in words is "five trillion, three hundred thirty-five billion, four hundred four million, two hundred three thousand, one hundred fifty-one".
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