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5335404430511 = 5681939390127
BaseRepresentation
bin100110110100011111011…
…1000101100010010101111
3200220001121111201120110102
41031220332320230102233
51144403402013234021
615203015001301315
71060320203244521
oct115507670542257
920801544646412
105335404430511
111777806786491
1272205419483b
132c9184b4992c
141463409cda11
1593bbd1ec00b
hex4da3ee2c4af

5335404430511 has 4 divisors (see below), whose sum is σ = 5335414388832. Its totient is φ = 5335394472192.

The previous prime is 5335404430501. The next prime is 5335404430547. The reversal of 5335404430511 is 1150344045335.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5335404430511 is a prime.

It is a super-2 number, since 2×53354044305112 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5335404430501) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4126871 + ... + 5263256.

It is an arithmetic number, because the mean of its divisors is an integer number (1333853597208).

Almost surely, 25335404430511 is an apocalyptic number.

5335404430511 is a deficient number, since it is larger than the sum of its proper divisors (9958321).

5335404430511 is an equidigital number, since it uses as much as digits as its factorization.

5335404430511 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9958320.

The product of its (nonzero) digits is 216000, while the sum is 38.

Adding to 5335404430511 its reverse (1150344045335), we get a palindrome (6485748475846).

The spelling of 5335404430511 in words is "five trillion, three hundred thirty-five billion, four hundred four million, four hundred thirty thousand, five hundred eleven".

Divisors: 1 568193 9390127 5335404430511