Base | Representation |
---|---|
bin | 110001101100010001… |
… | …001001010100001001 |
3 | 12002201110210202001111 |
4 | 301230101021110021 |
5 | 1333233121311411 |
6 | 40302245050321 |
7 | 3566132604151 |
oct | 615421112411 |
9 | 162643722044 |
10 | 53356041481 |
11 | 206a0104756 |
12 | a4109b69a1 |
13 | 50541442a2 |
14 | 2822337761 |
15 | 15c4317721 |
hex | c6c449509 |
53356041481 has 2 divisors, whose sum is σ = 53356041482. Its totient is φ = 53356041480.
The previous prime is 53356041443. The next prime is 53356041491. The reversal of 53356041481 is 18414065335.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 46865322256 + 6490719225 = 216484^2 + 80565^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53356041481 is a prime.
It is a super-2 number, since 2×533560414812 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (53356041491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26678020740 + 26678020741.
It is an arithmetic number, because the mean of its divisors is an integer number (26678020741).
Almost surely, 253356041481 is an apocalyptic number.
It is an amenable number.
53356041481 is a deficient number, since it is larger than the sum of its proper divisors (1).
53356041481 is an equidigital number, since it uses as much as digits as its factorization.
53356041481 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 172800, while the sum is 40.
The spelling of 53356041481 in words is "fifty-three billion, three hundred fifty-six million, forty-one thousand, four hundred eighty-one".
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