Base | Representation |
---|---|
bin | 11000010001101110101011… |
… | …00010100100001111000011 |
3 | 21000000121220101121020010111 |
4 | 30020313111202210033003 |
5 | 23444132434132132212 |
6 | 305313022153412151 |
7 | 14146664120245102 |
oct | 1410672542441703 |
9 | 230017811536114 |
10 | 53385731130307 |
11 | 16012841507174 |
12 | 5ba261940a057 |
13 | 23a3339663b44 |
14 | d27c515dc039 |
15 | 628a43258ea7 |
hex | 308dd58a43c3 |
53385731130307 has 2 divisors, whose sum is σ = 53385731130308. Its totient is φ = 53385731130306.
The previous prime is 53385731130241. The next prime is 53385731130337. The reversal of 53385731130307 is 70303113758335.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53385731130307 is a prime.
It is a super-3 number, since 3×533857311303073 (a number of 42 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (53385731130337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26692865565153 + 26692865565154.
It is an arithmetic number, because the mean of its divisors is an integer number (26692865565154).
Almost surely, 253385731130307 is an apocalyptic number.
53385731130307 is a deficient number, since it is larger than the sum of its proper divisors (1).
53385731130307 is an equidigital number, since it uses as much as digits as its factorization.
53385731130307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2381400, while the sum is 49.
The spelling of 53385731130307 in words is "fifty-three trillion, three hundred eighty-five billion, seven hundred thirty-one million, one hundred thirty thousand, three hundred seven".
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