Base | Representation |
---|---|
bin | 110001101110100110… |
… | …001100010110001101 |
3 | 12002211012022210121000 |
4 | 301232212030112031 |
5 | 1333323122111412 |
6 | 40310202330513 |
7 | 3600115655265 |
oct | 615646142615 |
9 | 162735283530 |
10 | 53395113357 |
11 | 20710170a63 |
12 | a421ab9a39 |
13 | 505c274541 |
14 | 28275c87a5 |
15 | 15c79844dc |
hex | c6e98c58d |
53395113357 has 128 divisors (see below), whose sum is σ = 87625566720. Its totient is φ = 32003112960.
The previous prime is 53395113353. The next prime is 53395113371. The reversal of 53395113357 is 75331159335.
53395113357 is a `hidden beast` number, since 53 + 3 + 9 + 511 + 33 + 57 = 666.
53395113357 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 53395113357 - 22 = 53395113353 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53395113353) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 190018057 + ... + 190018337.
It is an arithmetic number, because the mean of its divisors is an integer number (684574740).
Almost surely, 253395113357 is an apocalyptic number.
It is an amenable number.
53395113357 is a deficient number, since it is larger than the sum of its proper divisors (34230453363).
53395113357 is a wasteful number, since it uses less digits than its factorization.
53395113357 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 540 (or 534 counting only the distinct ones).
The product of its digits is 637875, while the sum is 45.
The spelling of 53395113357 in words is "fifty-three billion, three hundred ninety-five million, one hundred thirteen thousand, three hundred fifty-seven".
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