Base | Representation |
---|---|
bin | 100110110110101000011… |
… | …1000000001111111001011 |
3 | 200220111110212101101111222 |
4 | 1031231100320001333023 |
5 | 1144442310302330121 |
6 | 15205055050312255 |
7 | 1060542131254043 |
oct | 115552070017713 |
9 | 20814425341458 |
10 | 5340001214411 |
11 | 1779755521246 |
12 | 722b1772868b |
13 | 2c97382ac0c6 |
14 | 1466592d0723 |
15 | 93d8ba570ab |
hex | 4db50e01fcb |
5340001214411 has 2 divisors, whose sum is σ = 5340001214412. Its totient is φ = 5340001214410.
The previous prime is 5340001214357. The next prime is 5340001214459. The reversal of 5340001214411 is 1144121000435.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5340001214411 - 210 = 5340001213387 is a prime.
It is a super-2 number, since 2×53400012144112 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5340001211411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2670000607205 + 2670000607206.
It is an arithmetic number, because the mean of its divisors is an integer number (2670000607206).
Almost surely, 25340001214411 is an apocalyptic number.
5340001214411 is a deficient number, since it is larger than the sum of its proper divisors (1).
5340001214411 is an equidigital number, since it uses as much as digits as its factorization.
5340001214411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1920, while the sum is 26.
Adding to 5340001214411 its reverse (1144121000435), we get a palindrome (6484122214846).
The spelling of 5340001214411 in words is "five trillion, three hundred forty billion, one million, two hundred fourteen thousand, four hundred eleven".
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