Base | Representation |
---|---|
bin | 100110110110101001000… |
… | …1100010010110100010101 |
3 | 200220111112101221121222100 |
4 | 1031231102030102310111 |
5 | 1144442331431202240 |
6 | 15205101155552313 |
7 | 1060542520103415 |
oct | 115552214226425 |
9 | 20814471847870 |
10 | 5340023303445 |
11 | 1779766a39046 |
12 | 722b22bbb699 |
13 | 2c973ca4433c |
14 | 14665c200645 |
15 | 93d8d96be30 |
hex | 4db52312d15 |
5340023303445 has 24 divisors (see below), whose sum is σ = 9256116365496. Its totient is φ = 2847989052288.
The previous prime is 5340023303437. The next prime is 5340023303453. The reversal of 5340023303445 is 5443033200435.
5340023303445 is a `hidden beast` number, since 5 + 340 + 0 + 2 + 3 + 303 + 4 + 4 + 5 = 666.
It is an interprime number because it is at equal distance from previous prime (5340023303437) and next prime (5340023303453).
It can be written as a sum of positive squares in 4 ways, for example, as 315077897124 + 5024945406321 = 561318^2 + 2241639^2 .
It is not a de Polignac number, because 5340023303445 - 23 = 5340023303437 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6008439 + ... + 6839691.
It is an arithmetic number, because the mean of its divisors is an integer number (385671515229).
Almost surely, 25340023303445 is an apocalyptic number.
It is an amenable number.
5340023303445 is a deficient number, since it is larger than the sum of its proper divisors (3916093062051).
5340023303445 is a wasteful number, since it uses less digits than its factorization.
5340023303445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 974021 (or 974018 counting only the distinct ones).
The product of its (nonzero) digits is 259200, while the sum is 36.
The spelling of 5340023303445 in words is "five trillion, three hundred forty billion, twenty-three million, three hundred three thousand, four hundred forty-five".
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