Base | Representation |
---|---|
bin | 11000010010001010000000… |
… | …10011111101111010101001 |
3 | 21000002000210012112022111221 |
4 | 30021011000103331322221 |
5 | 23444403013241223322 |
6 | 305323450344222041 |
7 | 14151023606224132 |
oct | 1411050023757251 |
9 | 230060705468457 |
10 | 53400407367337 |
11 | 16018a928a4288 |
12 | 5ba543446a921 |
13 | 23a48380b1c74 |
14 | d28844824c89 |
15 | 6291019189c7 |
hex | 3091404fdea9 |
53400407367337 has 2 divisors, whose sum is σ = 53400407367338. Its totient is φ = 53400407367336.
The previous prime is 53400407367277. The next prime is 53400407367347. The reversal of 53400407367337 is 73376370400435.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 46222851990121 + 7177555377216 = 6798739^2 + 2679096^2 .
It is a cyclic number.
It is not a de Polignac number, because 53400407367337 - 239 = 52850651553449 is a prime.
It is not a weakly prime, because it can be changed into another prime (53400407367347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26700203683668 + 26700203683669.
It is an arithmetic number, because the mean of its divisors is an integer number (26700203683669).
Almost surely, 253400407367337 is an apocalyptic number.
It is an amenable number.
53400407367337 is a deficient number, since it is larger than the sum of its proper divisors (1).
53400407367337 is an equidigital number, since it uses as much as digits as its factorization.
53400407367337 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13335840, while the sum is 52.
The spelling of 53400407367337 in words is "fifty-three trillion, four hundred billion, four hundred seven million, three hundred sixty-seven thousand, three hundred thirty-seven".
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