53403433 has 4 divisors (see below), whose sum is σ = 56214160. Its totient is φ = 50592708.

The previous prime is 53403419. The next prime is 53403451. The reversal of 53403433 is 33430435.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-53403433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53403398 and 53403407.

It is not an unprimeable number, because it can be changed into a prime (53403533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1405335 + ... + 1405372.

It is an arithmetic number, because the mean of its divisors is an integer number (14053540).

Almost surely, 2^53403433 is an apocalyptic number.

It is an amenable number.

53403433 is a deficient number, since it is larger than the sum of its proper divisors (2810727).

53403433 is a wasteful number, since it uses less digits than its factorization.

53403433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2810726.

The product of its (nonzero) digits is 6480, while the sum is 25.

The square root of 53403433 is about 7307.7652534821. The cubic root of 53403433 is about 376.5792551316.

Adding to 53403433 its reverse (33430435), we get a palindrome (86833868).

The spelling of 53403433 in words is "fifty-three million, four hundred three thousand, four hundred thirty-three".