Base | Representation |
---|---|
bin | 100110110110110100011… |
… | …0100111000111111010111 |
3 | 200220112111212111110111212 |
4 | 1031231220310320333113 |
5 | 1144444121134404221 |
6 | 15205203003052035 |
7 | 1060555110616556 |
oct | 115555064707727 |
9 | 20815455443455 |
10 | 5340403044311 |
11 | 1779941326a75 |
12 | 72300a21101b |
13 | 2c97a061158a |
14 | 14669680dd9d |
15 | 93db1e7cb5b |
hex | 4db68d38fd7 |
5340403044311 has 4 divisors (see below), whose sum is σ = 5340481450824. Its totient is φ = 5340324637800.
The previous prime is 5340403044287. The next prime is 5340403044331. The reversal of 5340403044311 is 1134403040435.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5340403044311 - 230 = 5339329302487 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5340403044331) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39101000 + ... + 39237341.
It is an arithmetic number, because the mean of its divisors is an integer number (1335120362706).
Almost surely, 25340403044311 is an apocalyptic number.
5340403044311 is a deficient number, since it is larger than the sum of its proper divisors (78406513).
5340403044311 is an equidigital number, since it uses as much as digits as its factorization.
5340403044311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 78406512.
The product of its (nonzero) digits is 34560, while the sum is 32.
Adding to 5340403044311 its reverse (1134403040435), we get a palindrome (6474806084746).
The spelling of 5340403044311 in words is "five trillion, three hundred forty billion, four hundred three million, forty-four thousand, three hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •