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5340405240431 = 53100762363027
BaseRepresentation
bin100110110110110100011…
…1101010001001001101111
3200220112112000122001000122
41031231220331101021233
51144444122220143211
615205203122115155
71060555135364342
oct115555075211157
920815460561018
105340405240431
111779942596a48
1272300aaababb
132c97a0c00061
14146696c22459
1593db22636db
hex4db68f5126f

5340405240431 has 4 divisors (see below), whose sum is σ = 5441167603512. Its totient is φ = 5239642877352.

The previous prime is 5340405240421. The next prime is 5340405240433. The reversal of 5340405240431 is 1340425040435.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5340405240431 is a prime.

It is a super-2 number, since 2×53404052404312 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5340405240391 and 5340405240400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5340405240433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50381181461 + ... + 50381181566.

It is an arithmetic number, because the mean of its divisors is an integer number (1360291900878).

Almost surely, 25340405240431 is an apocalyptic number.

5340405240431 is a deficient number, since it is larger than the sum of its proper divisors (100762363081).

5340405240431 is a wasteful number, since it uses less digits than its factorization.

5340405240431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100762363080.

The product of its (nonzero) digits is 115200, while the sum is 35.

The spelling of 5340405240431 in words is "five trillion, three hundred forty billion, four hundred five million, two hundred forty thousand, four hundred thirty-one".

Divisors: 1 53 100762363027 5340405240431